2x^2-10=x^2-28

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Solution for 2x^2-10=x^2-28 equation: 



2x^2-10=x^2-28

We move all terms to the left:

2x^2-10-(x^2-28)=0

We get rid of parentheses

2x^2-x^2+28-10=0

We add all the numbers together, and all the variables

x^2+18=0

a = 1; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·1·18
Δ = -72
Delta is less than zero, so there is no solution for the equation

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